x^2-4.6x+2.4=0

Solution for x^2-4.6x+2.4=0 equation:

x^2-4.6x+2.4=0

a = 1; b = -4.6; c = +2.4;
Δ = b2-4ac
Δ = -4.62-4·1·2.4
Δ = 11.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.6)-\sqrt{11.56}}{2*1}=\frac{4.6-\sqrt{11.56}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.6)+\sqrt{11.56}}{2*1}=\frac{4.6+\sqrt{11.56}}{2}
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